Aball is thrown upward with an initial velocity of 4 ft/sec from a height of 10 feet. what is the maximum height that the ball will reach?

10.25 ft

Explanation:

According to the law of conservation of energy, the initial kinetic energy of the ball when it is thrown upward is entirely converted into gravitational potential energy when the ball reaches its maximum height. So we can write:

where

m is the mass of the ball

v = 4 ft/s is the initial speed

g = 32 ft/s^2 is the acceleration due to gravity

is the change in height of the ball

Re-arranging the equation, we find

And since the ball was thrown from a heigth of 10 feet, the maximum height reached is

h = 10 ft + 0.25 ft = 10.25 ft

10.248 ft                                  

Explanation:

Given that velocity u=4 ft/sec

Initial height=10 ft

We know that gravity is constant so we can apply

Here we need to find maximum height .When it velocity will become zero then attained height will be maximum so v=0 , =4 ft/sec.

Now by putting the values

So h=0.248 ft

So the attained maximum height=0.248+10

                                                    =10.248 ft                                  

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m