Inside a nasa test vehicle, a 3.50-kg ball is pulled along by a horizontal ideal spring fixed to a friction-free table. the force constant of the spring is 222 n/m. the vehicle has a steady acceleration of 5.00 m/s^2, and the ball is not oscillating. suddenly, when the vehicle's speed has reached 45.0 m/s, its engines turn off, thus eliminating its acceleration but not its velocity. a) find the amplitude.
b) find the frequency of the resulting oscillations of the ball.
c)what will be the ball's maximum speed relative to the vehicle?

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W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j