Awater tank has the shape of an inverted circular cone with base radius 2m and height 4m. if water is being pumped into the tank at a rate of 2 m3 / min, find the rate at which the water level is rising when the water is 3 m deep.

The volume of the tank is a circular cone, therefore it is given by:

V = πr²h/3

V = volume, r = base radius, h = height or water level

Differentiate both sides with respect to time t. The base radius r doesn't change over time so treat it as a constant:

dV/dt = πr²(dh/dt)/3

Given values:

dV/dt = 2m³/min

r = 2m

Plug in and solve for dh/dt:

2 = π(2)²(dh/dt)/3

dh/dt = 0.48m/min

The water level is increasing at a rate of 0.48m/min

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~

a displacement distance is size of displ