Crew members attempt to escape from a damaged submarine 141 m below the surface. what force must be applied to a pop-out hatch, which is 1.72 m by 0.859 m, to push it out at that depth? assume that the density of the ocean water is 1024 kg/m3 and the internal air pressure is at 1.00 atm.

20.9 x 10⁵ N

Explanation:

The external air pressure downwards and internal air pressure upwards will cancel out. TH net pressure to be faced will be due to water column of 141 m depth.

Pressure of water = hdg = 141 x 1024 x 9.8 = 14.15 x 10⁵ Pa

Area of hatch = 1.72 x 0.859 = 1.4775 sq m.

Total force required = area x pressure = 14.15 x 10⁵ x 1.4775 = 20.9 x 10⁵ N.

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~

molecules are free to separate from each other and will take on the shape of the container. molecules move completely at random and high speeds. they vibrate in a fixed position and do not move around much. molecules expand to the edge of their container.