In a steam engine the pressure and volume of steam satisfy the equation pv1.4 = k, where k is a constant. (this is true for adiabatic expansion, that is, expansion in which there is no heat transfer between the cylinder and its surroundings.) calculate the work done by the engine during a cycle when the steam starts at a pressure of 160 lb/in2 and a volume of 300 in3 and expands to a volume of 1000 in3.

3821.99 ft-lb

Explanation:

Given:

Initial pressure, P = 160 lb/in²

Initial volume, V₁ = 300 in³

thus,

Final volume, V₂ = 1000 in³

Now

Work done (W) =

also,

or

substituting the value in the formula for work done, we get

W =

on substituting the values, we get

W =

on intergerating

W =

or

W =

or

W = 45863.89 in.pounds

or

W = 45863.89 in.pounds × (1 ft/12 in) = 3821.99 ft-lb

what type of charge does it have? negative

the answer would be 32*f