The acceleration of a bus is given by ax (t) = at, where a = 1.2 m/s3.if the bus's velocity at time t = 1.0s is 5.0 m/s, what is its velocity at time t = 2.0 s?

We are given the acceleration of the bus as a function of time:

a(t) = 1.2t

Let the velocity also be a function of time v(t).

Since a(t) is the change of v(t) over time, we can use the fundamental theorem of calculus to determine the velocity at t = 2s, or v(2), given that:

a(t) = 1.2t

v(1) = 5

v(2) - v(1) =

v(2) - 5 =

v(2) - 5 = 0.6t² evaluated between t = 1 and t = 2

v(2) - 5 = 0.6(4) - 0.6(1)

v(2) = 1.8 + 5

v(2) = 6.8m/s

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

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