When a 83.0 kg. person climbs into an 1600 kg. car, the car's springs compress vertically 1.6 cm. what will be the frequency of vibration when the car hits a bump? (ignore damping.)

the correct answer is f= 0.8747 oscillations/sec

Explanation:

The first bit of info allows you to find the spring constant;  

K = force of compression/compression  

where the force of compression is the "added" weight on the spring;  

K = (83)(9.8)/(.016)              K= 50837.5

Once you have ,K , you can use the frequency relation between ,K, and total mass on spring ,      M= 1600Kg + 83Kg   M=1683 kg, as;  

f =(1/2Pi)SqRt[K/M] oscillations/sec

f= (1/2 (3.1416)SqRt (50837.5/1683)

f=1/6.2832)SqRt 30.2065

f=  0.1592 *5.4960            f= 0.8747 oscillations/sec

they are non-matter

explanation:

they are non-matter. basically, any type of energy or any abstract concept is an example of something that does not matter. other examples include dreams, magnetism, radio, and hate

there is no correct list among the choices you've provided.

the list might look something like this:

-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

-- tuba

since i had to make up the list myself, i made it easy on myself, and i didn't try to shuffle the string instruments and woodwinds into it too.