Atennis player receives a shot with the ball (0.060 0 kg) traveling horizontally at 20.0 m/s and returns the shot with the ball traveling horizontally at 40.0 m/s in the opposite direction. (a) what is the impulse delivered to the ball by the tennis racket? (b) some work is done on the system of the ball and some energy appears in the ball as an increase in internal energy during the collision between the ball and the racket. what is the sum w 2 deint for the ball?

a) 3.6 N.s

b) 36 J

Explanation:

Given:

The mass of ball, m = 0.06 kg

The initial velocity v₁ = -20 m/s

final velocity v₂ = 40 m/s  

Now,

The impulse  is given as:

I= change in momentum

or

I = m( v₂ - v₁)

or

I = 0.06 × (40 - (-20))

or

I = 3.6 N.s

(b) work done = change in kinetic energy

W.D = ΔK.E

W.D =

on substituting the values

W.D =  

W.D = 36 J

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

the answer would be a