You’re inside a metal building that blocks radio waves, but you’re trying to make a call with your cell phone, which broadcasts at a frequency of 950 mhz. down the hall from you is a narrow window measuring 35 cm wide. what’s the horizontal angular width of the beam (i. e., the angle between the first minima) from your phone as it emerges from the window?

θ= 128.896°

Explanation:

In the Given question

f= 950 MHz

width of slit =35 cm = 0.35m

the expression to calculate angular width

wavelength is

λ= 0.315 m

therefore angular width

on further solving we get

θ= 2*64.448

θ= 128.896°

hence the horizontal angular width θ= 128.896°

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get

you have to draw the persons position over there