Acrate of mass 10.0 kg is pulled up a rough incline with an initial speed of 1.50 m/s. the pulling force is 100 n parallel to the incline, which makes an angle of 20.08 with the horizontal. the coefficient of kinetic friction is 0.400, and the crate is pulled 5.00 m. (a) how much work is done by the gravitational force on the crate? (b) determine the increase in internal energy of the crate–incline system owing to friction. (c) how much work is done by the 100-n force on the crate? (d) what is the change in kinetic energy of the crate? (e) what is the speed of the crate after being pulled 5.00 m?

unable to answer the rest since your question is incomplete

v=ir = 3x15 =45 v

compass can be used day and night, cloudy or sunny

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.