The distance required for a car to come to a stop will vary depending on how fast the car is moving. suppose that a certain car traveling down the road at a speed of 10 m/s can come to a complete stop within a distance of 20 m . assuming the road conditions remain the same, what would be the stopping distance required for the same car if it were moving at speeds of 5 m/s, 20 m/s, or 40 m/s ?

The stopping distance required for the same car at speeds of 5 m/s, 20 m/s, or 40 m/s is 5m, 80m, and 320 m.

We know that according to the third equation of motion,

given to us

speed of the car, u = 10 m/s

Distance, s = 20 m

Substitute the value to find the deceleration,

The stopping distance required for the same car,

A.) speed, u = 5 m/s

B.) speed, u = 20 m/s

C.) speed, u = 40 m/s

Hence, the stopping distance required for the same car at speeds of 5 m/s, 20 m/s, or 40 m/s is 5m, 80m, and 320 m.

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when speed becomes v = 5 m/s

when speed = 20 m/s

when speed = 40 m/s

Explanation:

Initial speed of the car is given as

now we have

stopping distance = 20 m

final speed = 0

now we have

now we have

now we know that

all conditions remains the same

so stopping distance depends on the speed as

now when speed becomes v = 5 m/s

so it is half of the above speed

so the stopping distance becomes 1/4 times

when speed = 20 m/s that is double the given speed

then the stopping distance becomes 4 times

when speed = 40 m/s that is four times the given speed

then the stopping distance becomes 16 times

2b2t

explanation:

2b2t