You are looking down on a n = 24 turn coil in a magnetic field b = 1 t which points directly down into the screen. if the diameter of the coil d = 3.7 cm, and the field goes to zero in t = 0.08 seconds, what would be the magnitude of the voltage (in volts) and direction of the induced current? indicate the direction of the current by the sign in front of your voltage: counterclockwise is positive, clockwise is negative.

E = 0.3225 Volts

Explanation:

Given:

N = 24 turns

magnetic field, B = 1 T

Diameter of the coil, d = 3.7 cm = 0.037 m

area, A = =

Time, t = 0.08 seconds

Now, The induced Emf (E) is given as;

E = -d(flux)/dt

now, the flux is given as:

Flux = NBA = 24 × 1 × 0.00107 = 0.0258 Wb

Now, E = -0.0258/0.08

or

E = 0.3225 Volts

The current is opposite to the flux, thus the direction of the current will be anti-clockwise

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)

answer; i believe the correct answer is (40,000 j) good luck