In a hurricane, air moves along the ocean surface into the eye of the hurricane. at the eyewall the temperature is still t2=303k but the pressure has dropped to p2=0.900bars . in addition, near the eyewall the air becomes saturated with water, and each kilogram of air contains about 28 grams of liquid water. this water evaporates when heat is adsorbed from the ocean at t2=303k. calculate δs2, the entropy change in moving 1.00 kilogram of air from the reference state to the eyewall. include both the entropy increase from the pressure change of the air and from the water evaporation. assume for water at t=303k δhvap=45.0kjmol−1

Ithink the answer is fusion 

Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.