Assume a small 11 kg crate is attached to a parachute. the chute pulls up on the crate with 150 n.
a. find fnet
b. find a
m/s²
c. find v 5 seconds after release
m/s
i'm really stuck on this.

Explanation:

a. The net force is the upward force of the chute minus the weight of the crate.

∑F = F − mg

∑F = 150 N − (11 kg) (9.8 m/s²)

∑F = 42.2 N

b. From Newton's second law, the net force equals the mass times acceleration:

∑F = ma

42.2 N = (11 kg) a

a = 3.84 m/s²

c. Acceleration is the change in velocity over change in time.  Assuming the crate is released from rest:

v = at + v₀

v = (3.84 m/s²) (5 s) + (0 m/s)

v = 19.2 m/s

co2reflects heat radiation back to earth buning coal and oil emits co2 globe warms

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.