The rear window of a van is coated with a layer of ice at 0°c. the density of ice is 917 kg/m3, and the latent heat of fusion of water is 3.35 x 105 j/kg. the driver of the van turns on the rear-window defroster, which operates at 12 v and 28 a. the defroster directly heats an area of 0.44 m2 of the rear window. what is the maximum thickness of ice above this area that the defroster can melt in 4.5 minutes?

thickness of ice melted = 1.242*10^{-3} m

Explanation:

power delivered = V*I = 12 * 28 =    336 Watts

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heat delivered = power * time = 336 W * 300 seconds =   168000 Joules

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mass of ice melted

mass of ice melted = 97200 J / 335000 J/kg = 0.5014 kg

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volume of ice melted = mass / density =  0.5014 / 917 = 5.46*10{-4} m3

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thickness of ice melted = volume / area = 5.46*10{-4} / 0.44   =  1.242*10^{-3} m

i guess that visual aids present persuasive examples to what you are presenting, some factors would be theme (does it fit with the color, information, what you are presenting), size (can you see it, is it a big enough span of data/information), and overall look of the visual aid.

hope this : )