At some instant and location, the electric field associated with an electromagnetic wave in vacuum has the strength 98.5 v/m. find the magnetic field strength, the energy density, and the power flow per unit area, all at the same instant and location.

Explanation:

As we know that the electric field strength in vacuum due to electromagnetic waves is given as

now we know the relation between electric field and magnetic field as

For energy density we know that

Power flow per unit area is given as

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.