Fig. 28-9 shows the cross-section of a hollow cylinder of inner radius a = 5 cm and outer radius b = 7 cm. a uniform current density j = 1 a/cm2 flows through the cylinder. calculate the magnitude of the magnetic field at a distance d = 10 cm from the axis of the cylinder.

1.507×10⁻⁴ T

Explanation:

a = 5 cm = 0.05 m

b = 7 cm = 0.07 m

j = 1 A/cm²

Distance from magnetic field = d = 10 cm = 0.1 m

μ₀ = Vacuum permeability = 4π×10⁻⁷ H/m

Magnetic of hollow cylinder

∴ Magnitude of the magnetic field at a distance d = 10 cm from the axis of the cylinder is 1.507×10⁻⁴ T

answer; i believe the correct answer is (40,000 j) good luck

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