An astronaut leaves earth in a spaceship at a speed of 0.96 c relative to an observer on earth. the astronaut's destination is a star system 14.4 light-years away (one light-year is the distance light travels in one year.) according to the astronaut, how long does the trip take?

Answerthe force between the charges will be  f/9 (one-ninth of force f)explanationcoulomb's law relates the magnitudes  two point charges q₁ and q₂, the distance, r, between the charges, and the electrostatic force, f, between the two charges:     k represents coulomb's constant, k = 8.99×10⁹ n·m²/c².note that if we have r = 3r, then   

Shania is trying to determine the oldest geologic unit on this map and the reason to why is she unable to do so is that  the units are all the same age.. when there is the same age, there will be no oldest geologic unit and that i cannot be credible.