The crate, which sets on a 10 degree incline, has a weight of 3433.5 n and is subjected to a towing force p acting at a 20 degree angle with the horizontal. if the coefficient of static friction is µs = 0.5, determine the force p needed to just start the crate moving down the plane.

P = 981 N

Explanation:

Given

Angle of the incline θ = 10°

Angle of the towing force φ =20°

Weight of the crate W = 3433.5 N

The coefficient of static friction µ = 0.5

Solution

Forces Acting along the ramp

Forces acting perpendicular to the ramp

Substituting the value of N we get

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.