Acharge is accelerated from rest through a potential difference v and then enters a uniform magnetic field oriented perpendicular to its path. the field deflects the particle into a circular arc of radius r. if the accelerating potential is tripled to 3v, what will be the radius of the circular

Explanation:

Case 1:

= potential difference through which the charge is accelerated = V

= mass of the charge

= magnitude of charge

= speed gained by the charge due to potential difference

Using conservation of energy

Kinetic energy gained = Electric potential energy lost

= magnitude of magnetic field

= Radius of arc

Radius of arc is given as

                               eq-1

Case 2:

= potential difference through which the charge is accelerated = 3V

= mass of the charge

= magnitude of charge

= speed gained by the charge due to potential difference

Using conservation of energy

Kinetic energy gained = Electric potential energy lost

= magnitude of magnetic field

= Radius of arc

Radius of arc is given as

Using eq-1

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

the assestment will probley apele with cause and effect