Two manned satellites approach one another at a relative velocity of =0.210v=0.210 m/s, intending to dock. the first has a mass of =4.00×103m1=4.00×103 kg and the second a mass of =7.50×103m2=7.50×103 kg. if the two satellites collide elastically rather than dock, what is their final relative velocity?

Explanation:

It is given that,

Relative velocity of two manned satellites, v = 0.210 m/s

Mass of first satellite,

Mass of other satellite,

The two satellites collide elastically rather than dock, we need to find their final velocities. Let v' is the final velocity. We know that in an elastic collision, both momentum and kinetic energy remains constant.

Also, the relative velocity of approach between two satellites before collision is same as the relative velocity of separation after collision. So, their final relative velocity is 0.210 m/s but in opposite direction.

the answer is b ) square root of 5

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2