Awire with a mass of 1.50 g/cm is placed on a horizontal surface with a coefficient of friction of 0.200. the wire carries a current of 1.52 a eastward and moves horizontally to the north. what are the magnitude and the direction of the smallest magnetic field that enables the wire to move in this fashion?

0.193 T

Inward direction

Explanation:

= Mass per unit length of wire = 1.50 g/cm = = 0.15 kg/m

= magnitude of current = 1.52 A

= magnitude of magnetic field = ?

= mass of the wire

= length of the wire

μ = Coefficient of friction = 0.200

For the wire to move,

magnetic force = frictional force

= μ

(1.52) = (0.200) (9.8)

(1.52)   = (0.200) (9.8)

(1.52)   = (0.200) (9.8) (0.15)

= 0.193 T

Direction of magnetic force is towards north and current is directed towards east. hence using right hand rule, the direction of magnetic field comes out to be in inward direction.