In lacrosse, a ball is thrown from a net on the end of a stick by rotating the stick and forearm about the elbow. if the angular velocity of the ball about the elbow joint is 30.3 rad/s30.3 rad/s and the ball is 1.35 m1.35 m from the elbow joint, what is the velocity of the ball?

40.91 m/s

Explanation:

w = angular velocity of the ball about the elbow joint = 30.3 rad/s

r = radius of circular turn = distance of the ball from the elbow joint = 1.35 m

v = linear velocity of the ball

Linear velocity of the ball is given as

v = r w

Inserting the values given above in the equation

v = (1.35) (30.3)

v = 40.91 m/s

this could be newton#'s law of cooling. the cooling curve is exponential

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