If a spring stretches 3 cm when a 2 kg mass is hung from it, how far will it stretch when a 6 kg mass is hung from it? show work. use hooke's law.

displacement (x2) = 0.09 meters

Explanation:

let the force by the spring be Fs , force due to gravity be Fg, displacement when 2 kg mass is hung be x1 and the displacement when 6 kg mass is hung be x2.

take the upward direction as positive.

then, for both cases:

Ftot = Fs + Fg = 0 , the block gets to a complete stop.

for when 2 kg mass is hung:

Fs = Fg

k×x1 = m1×g

k = m1×g/x1 = [(2)×(9.8)]/(0.03) = 653.3 N/m

then because k remain constant since we using the same string,

for when 6 kg mass is hung:

Fs = Fg

k×x2 = m2×g

x2 = [(6)×(9.8)]/(653.3) = 0.09 meters

therefore, the string will stretch for a displacement of 0.09 meters when the 6 kg mass is hung.

and 1and 1

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.