A16.0-m uniform ladder weighing 480 n rests against a frictionless wall. the ladder makes a 55.0° angle with the horizontal. (a) find the horizontal and vertical forces the ground exerts on the base of the ladder when an 850-n firefighter has climbed 3.80 m along the ladder from the bottom.
(b) if the ladder is just on the verge of slipping when the firefighter is 9.40 m from the bottom, what is the coefficient of static friction between ladder and ground?

horizontal force component 535.00 N

vertical force component 1330 N

Explanation:

from equilibrium condition at A

FROM equilibrium condition

N_1 = mg +850

       = 480 + 850

       = 1330 N

horizontal force component

f_2 = N_2

      = 535.00 N

vertical force component

N_1 = 1330 N

B) Coefficient of friction between ladder and ground when fire fighter is 9.4 m away from ground

N_2 =517.71 N

Thus coefficient of friction is

      =                     [f_2 = N_2]

       = 0.38

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.