Acoin of mass .005 kg dropped from a height of 3 m. how much potential energy does it have right before it hits the ground? assume there is no air resistance. acceleration due to gravity is g=9.8 m/s2

0 J

Explanation:

Gravitational potential energy is:

PE = mgh

where m is mass, g is acceleration due to gravity, and h is the height.

Right before the coin hits the ground, its height above the ground is 0 m, so the potential energy is:

PE = mgh

PE = (0.005 kg) (9.8 m/s²) (0 m)

PE = 0 J

where is the photo and the answer choices?

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm