Acampground official wants to measure the distance across an irregularly-shaped lake, but can't do so directly. he picks a point south of the lake. from that point to the left side of the lake, the distance is 105 meters. from that point to the right side of the lake is 119 meters. the angle between these two measurements is 83 degrees. how far is it across the lake?

149 m

Explanation:

The distances across the lake is forming a triangle.  

let the distance between the point and the left side be 'x'

and the distance between the point and the right be 'y'

and the distance across the lake be 'z' and the angle opposite to 'z' be 'Z' given:

∠Z = 83°

x = 105 m

y = 119 m

Now, applying the Law of Cosines, we get  

z² = x² + y² - 2xycos(Z)  

Substituting the values in the above equation, we get

z² = 105² + 119² - 2×105×119×cos(83°)

or

z = √22140.48

or

z = 148.796 m ≈ 149 m

The point is 149 m across the lake

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

i think the answer is tomato juice? not entirely sure though