What is the magnitude of the maximum stress that exists at the tip of an internal crack having a radius of curvature of 3.5 × 10-4 mm (1.378 × 10-5 in.) and a crack length of 4.5 × 10-2 mm (1.772 × 10-3 in.) when a tensile stress of 170 mpa (24660 psi) is applied?

Given:

applied tensile stress, = 170 MPa

radius of curvature of crack tip,   =   mm

crack length = mm

half of internal crack length, a =

a =  

Formula Used:

Solution:

Using the given formula:

= 2726 MPa (395372.9 psi)

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.

33: i think it’s b