Abasketball player grabbing a rebound jumps 76.0 cm vertically. how much total time (ascent and descent) does the player spend (a) in the top 15.0 cm of this jump and (b) in the bottom 15.0 cm? do your results explain why such players seem to hang in the air at the top of a jump?

Part a)

Part b)

So for top 15 cm the time interval is sufficiently larger than the time interval of last 15 cm

Explanation:

Part a)

Maximum height reached is

H = 76 cm

now the velocity of the player at starting position is given as

time taken by it in top 15 cm position is given as

so total time in that position is double because in that position first it will go up and then go down

Part b)

Now for bottom position of 15 cm first we will find the time to reach (76 - 15)cm have

now for total time to drop

so time interval of last 15 cm is given as

So for top 15 cm the time interval is sufficiently larger than the time interval of last 15 cm

car a and b are moving in opposite directions

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