Consider the mechanism. step 1: 2a↽−−⇀b+c equilibrium step 2: b+d⟶e slow overall: 2a+d⟶c+e determine the rate law for the overall reaction, where the overall rate constant is represented as

Answer : The rate law for the overall reaction is,

Explanation :

As we are given the mechanism for the reaction :

Step 1 :    (equilibrium)

Step 2 :     (slow)

Overall reaction :

First we have to determine the equilibrium constant from step 1.

The expression for equilibrium constant will be,

Form this, the value of [B] is,

      ............(1)

Now we have to determine the rate law from the slow step 2.

The expression for law will be,

      .............(2)

Now put equation 1 in 2, we get:

Therefore, the rate law for the overall reaction is,

neither accurate nor precise.