Aloop of radius r = 3.0 cm is placed parallel to the xy-plane in a uniform magnetic field = 0.75 t . the resistance of the loop is 18 ω. starting at t = 0, the magnitude of the field decreases uniformly to zero in 0.15 seconds. what is the magnitude of the electric current produced in the loop during that time?

i = 7.777 × 10⁻⁴ A = 0.77 mA

Explanation:

Given:

loop radius, r = 3.0 cm = 0.03 m

Area, A = π x r² = π x 0.03² = 0.0028 m²

Magnetic Field, B = 0.75 T

Loop resistance, R = 18 Ω

time, t = 0.15 seconds

Now,

the induced emf is given as:

EMF =

also

EMF = i x R

Where, i is the current flowing

equating both the formulas for EMF, we get

or

substituting the values in the above equation we get

or

the magnitude of the current, i = 7.777 × 10⁻⁴ A = 0.77 mA

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