Awheel of moment of inertia of 5.00 kg∙m2 starts from rest and accelerates under a constant torque of 3.00 n∙m for 8.00 s. what is the wheel's rotational kinetic energy at the end of 8.00 s?

The wheel's rotational kinetic energy is 57.6 J.

Explanation:

Given that,

Moment of inertia = 5.00 kg.m²

Torque = 3.00 N.m

Time = 8.00 s

We need to calculate the angular acceleration

Using formula of the torque act on the wheel

Where, I = moment of inertia

= angular acceleration

= torque

Put the value into the formula

We need to calculate the final angular velocity

Initially wheel at rest so initial velocity  is zero.

Using formula of angular velocity

Put the value into the formula

We need to calculate the rotational kinetic energy of the wheel

Using formula of the rotational kinetic energy

Hence, The wheel's rotational kinetic energy is 57.6 J.

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"the visibilities of vector-x and vector-y in the drawing provided with the question are identical and nonexistent."