Physics, 23.07.2019 04:20 meredith48034
Given that the initial rate constant is 0.0191 s-1 at an initial temperature of 24°c, what would the rate constant be at a temperature of 120°c for a reaction with an activation energy of 43.4 kj/mol?
Answers: 3
= ![\frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]](/tpl/images/0122/1017/f680d.png)
is 0.0191 
, 
is 24 degree celsius equals 297 K, 
is 120 degree celsius equals 393 K, and 
is 43.4 kJ/mol or 43400 J/mol.![\frac{-43400 J/mol}{8.314 j/mol K}[\frac{1}{393} - \frac{1}{297}]](/tpl/images/0122/1017/b56f8.png)
= 
= 1.40 
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Given that the initial rate constant is 0.0191 s-1 at an initial temperature of 24°c, what would the...
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