Abox rests on the (horizontal) back of a truck. the coefficient of static friction between the box and the surface on which it rests is 0.24. what maximum distance can the truck travel (starting from rest and moving horizontally with constant acceleration) in 3.0 s without having the box slide?

The distance is 11 m.

Explanation:

Given that,

Friction coefficient = 0.24

Time = 3.0 s

Initial velocity = 0

We need to calculate the acceleration

Using newton's second law

...(I)

Using formula of friction force

....(II)

Put the value of F in the equation (II) from equation (I)

....(III)

Put the value in the equation (III)

We need to calculate the distance,

Using equation of motion

Hence, The distance is 11 m.

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.