Aburglar attempts to drag a 108 kg metal safe across a polished wood floor assume that the coefficient of static friction is 0.4, the coefficient of kinetic friction is 0.3, and that the burglar can apply a pushing force of 534 n on the metal safe. what is the acceleration of the metal safe across floor?

2.00 m/s²

Explanation:

Given

The Mass of the metal safe, M = 108kg

Pushing force applied by the burglar,  F = 534 N

Co-efficient of kinetic friction, = 0.3

Now,

The force against the kinetic friction is given as:

Where,

N = Normal reaction

g= acceleration due to the gravity

Substituting the values in the above equation, we get

or

Now, the net force on to the metal safe is

Substituting the values in the equation we get

or

also,

acceleration of the safe

Therefore, the acceleration of the metal safe will be

acceleration of the safe=

or

 acceleration of the safe=

or

acceleration of the safe=

Hence, the acceleration of the metal safe will be  2.00 m/s²

double the distance = divide strength by 4

v=ir = 3x15 =45 v