A0.5-kg uniform meter stick is suspended by a single string at the 30-cm mark. a 0.2-kg mass hangs at the 80 cm mark. what mass hung at the 10-cm mark will produce equilibrium?

0.50 kg

Explanation:

From the equilibrium condition, torques must be balanced. Torque is the product of force and distance.

The unknown mass is at a distance of 20 cm from the suspension point (30 cm). The 0.20 kg is at a distance of 0.50 cm from that same point.

Clockwise torques must equal anti clockwise torques.

So (0.20 m)  (M g) = (0.50 m)(0.20 g)

Here M is the unknown mass and g stands for gravity.

⇒ Unknown mass = M = (0.50 × 0.20 ) ÷ (0.20)= 0.50 kg

nec chapter 5 contains

c. information on special occupancy areas

nec chapter 6 covers

a. special equipment

which of the following rules contain the words shall or shall not and must be adhered to?

b. mandatory rules

which of the following rules identify actions that are allowed but not required and typically cover options or alternative methods?

c. optional rules

which of the following serves as the introduction to the nec and provides an overview of the book?

a. nec article 90

organizations that test products for safety are

c. nrtls

the nec is published by the

a national fire protection association

the nec is divided into

b. 9 chapters

the nec provides informative annexes for

c. informational materials and examples

two terms from nec article 100 that trainees should become familiar with are

b. labeled and listed

explanation:

this a false

explanation: