Two particles are fixed to an x axis: particle 1 of charge -3.91 x 10^-7 c is at the origin and particle 2 of charge +3.91 x 10^-7 c is at x2 = 12.8 cm. midway between the particles, what the magnitude of the net electric field?

Net electric field,

Explanation:

It is given that,

Charge on particle 1,

Charge on particle 2,    

Particle 1 is at origin and particle 2 is at x₂ = 12.8 cm = 0.128 m

The magnitude of the net electric field at the midway between the particles is given by :

E = 214782.71 N/C

We know that for a positive charge the direction of field is outwards and for a negative charge the direction of electric field is inwards. Here, for two charges, the net electric field,

So, the magnitude of the net electric field is . Hence, this is the required solution.

vapour or gas assuming atmospheriv pressure