Aclock face has negative point charges –q, –2q, – –12q fixed at the positions of the corresponding numerals. the clock hands do not perturb the net field due to the point charges. at what time does the hour hand point in the same direction as the electric field vector at the center of the dial? break the time into (a) hours and (b) minutes. (hint: use symmetry.)

it doesn't. it was imagined up in the middle ages.

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.

i dont have a visual in front of me, but i can you reason to try to get the right one. the graph should look like this, 0 to 6 there is a spike, 12 to 14 there should be a very low point. slight increase in the graph at 12 to 14, and flat 14 to 18

explanation: