Calculate the amount of energy in kilojoules needed to change 261 g of water ice at −10 ∘c to steam at 125 ∘c. the following constants may be useful: cm (ice)=36.57 j/(mol⋅∘c) cm (water)=75.40 j/(mol⋅∘c) cm (steam)=36.04 j/(mol⋅∘c) δhfus=+6.01 kj/mol δhvap=+40.67 kj/mol