Asolid block of mass m2 = 0.88 kg, at rest on a horizontal frictionless surface, is connected to a relaxed spring (with spring constant k = 146 n/m whose other end is fixed. another solid block of mass m1 = 1.25 kg and speed v1 = 2.40 m/s collides with the 0.88 kg block. if the blocks stick together, what is their speed immediately after the collision?

b. false

explanation:

suppose a rock in free fall is dropped off a cliff. after falling for 5 seconds, its speed would not be 100 m/s.

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m