Which of the following can penetrate the deepest ( explain)
a) 3mev electron
b) 10mev alpha
c) 0.1 mev auger
d) 400kev proton

3MeV electron

Explanation:

m_e={9.1\times 10^{-31}      m_α=4\times m_e    m_a={9.1\times 10^{-31}

m_p=1.67\times 10^{-27}

(a)  K.E. Energy of electron ==3MeV

=1.05\times10^{18}

(b) K.E. Energy of alpha particle ==10MeV

=0.88\times10^{18}

(c) K.E. Energy of auger particle ==0.1MeV

=0.035\times10^{18}

(d)  K.E. Energy of proton particle ==400keV

=0.766\times10^{14}

from (a),(b),(c),and (d) we can clearly say that the velocity of the electron is more so the penetration of the electron will be deepest.

absorption lines are where light has been absorbed by the atom thus you see a dip in the spectrum whereas.

emission spectra have spikes in the spectra due to atoms releasing photons at those wavelengths.

explanation:

which three statements are true about all alloys?