The focal length of a planar-convex thin lens in air is 250.0 cm. the glass it is made of has an index of 1.530. determine the radii of curvature of its surfaces. what would happen to the radii if n was reduced to 1.500?

The radii of curvature of its surface is 0.00212 cm and after reduced the radii of curvature of its surface is 0.002 cm.

Explanation:

Given that,

Refractive index = 1.530 cm

After reduce refractive index = 1.500

Focal length =250.0 cm

Radius of curvature of plane mirror

We need to calculate the radii of curvature of lens

Using formula of lens

Put the value into the formula

If n was reduced to 1.500

Then, the radii of curvature of lens

Hence, The radii of curvature of its surface is 0.00212 cm and after reduced the radii of curvature of its surface is 0.002 cm.

the answer would be c. motion and direction

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