If the plate separation of an isolated charged parallel-plate capacitor is doubled: a. the electric field is doubled
b. the potential difference is halved
c. the charge on each plate is halved
d. the surface charge density on each plate is doubled
e. none of the above

Explanation:

The electric field of an isolated charged parallel-plate capacitor is given by :

........(1)

Where

q is the electric charge

A is the area of cross section of parallel plate

It is clear from equation (1) that the electric field of a parallel plate capacitor is directly proportional to the charge on the plate and inversely proportional to the area of cross section of a plate.

So, the correct option is (E) i.e. "none of the above".

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explanation:

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