If the current density in a wire or radius r is given by j-k+5,0f wire? r, what is the current in the wire?

I = (K+5)

Explanation:

Given :

J = k+5

Now selecting a thin ring in the wire of radius "r" and thickness dr.

Current through the thin ring is

dI = J X 2πrdr

dI = (K+5) x 2πrdr

Now integrating we get

I =

I = (K+5) 2π

I = (K+5) 2π

I = (K+5)

an energy transformation flow diagram is shown

where is it ?

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.