A0.350 kg iron horseshoe that is initially at 600°c is dropped into a bucket containing 21.9 kg of water at 21.8°c. what is the final equilibrium temperature (in °c)? neglect any heat transfer to or from the surroundings. do not enter units.

Explanation:-

As we know that,  

where,

= mass of iron horseshoe = 0.35 kg = 350 g (1kg=1000g[/tex]

= mass of water = 21.9 kg = 21900 g

= final temperature = ?

= temperature of iron horseshoe =

= temperature of water =

= specific heat of iron horseshoe =

= specific heat of water =  

Now put all the given values in equation (1), we get

Therefore, the final equilibrium temperature is .

come closer and become far apart and become steam/gas