A75.0-cm-long wire of mass 5.625 g is tied at both ends and adjusted to a tension of 35.0 n. when it is vibrating in its second overtone, find (a) the frequency and wavelength at which it is vibrating and (b) the frequency and wavelength of the sound waves it is producing.

Part a)

wavelength = 50 cm

frequency = 136.6 Hz

Part b)

wavelength = 2.48 m

frequency = 136.6 Hz

Explanation:

As we know that linear mass density of the wire is given as

now we know that tension in wire is given by

T = 35 N

so the speed of wave in the string is given as

Part a)

now wire is vibrating in second overtone

so here we have

now frequency is given as

Part b)

Frequency will remain same as it depends on source only

so frequency of sound wave will be f = 136.6 Hz

also for wavelength we have

report

explanation:

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.