Amoving particle encounters an external electric field that decreases its kinetic energy from 9650 ev to 8900 ev as the particle moves from position a to position b the electric potential at a is 56.0 v and that at b is 19.0 v determine the charge of the particle include the algebraic sign or with your answer.

Charge,

Explanation:

A moving particle encounters an external electric field that decreases its kinetic energy from 9650 eV to 8900 eV as the particle moves from position A to position B The electric potential at A is 56.0 V and that at B is 19.0 V. We need to find the charge of the particle.

It can be calculated using conservation of energy as :

q = -20.27 e

Hence, this is the required solution.

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

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