An earthquake 45 km from a city produces p and s waves that travel outward at 5000 m/s and 3000 m/s, respectively. once city residents feel the shaking of the p wave, how much time do they have before the s wave arrives in seconds?

The S wave arrives 6 sec after the P wave.

Explanation:

Given that,

Distance of P = 45 km

Speed of p = 5000 m/s

Speed of S = 3000 m/s

We need to calculate the time by the P wave

Using formula of time

Where, D = distance

v = speed

t = time

Put the value in to the formula

Now, time for s wave

The required time is

Hence, The S wave arrives 6 sec after the P wave.

probably not if net force is zero