Earth has a mass of 5.97 x 10*kg, and a mean radius of 6.38 x 108m. what would be the orbital speed and period of a satellite in
orbit 1.44 x 109 m above earth?

Explanation:

Centripetal acceleration = acceleration due to gravity

v² / r = GM / r²

Solving for velocity:

v = √(GM / r)

Given:

G = 6.67×10⁻¹¹ m³/kg/s²

M = 5.97×10²⁴ kg

r = 6.38×10⁸ m + 1.44×10⁹ m = 2.078×10⁹ m

v = √(6.67×10⁻¹¹ × 5.97×10²⁴ / 2.078×10⁹)

v = 438 m/s

Period is the time to travel one circumference:

T = 2πr / v

T = 2π (2.078×10⁹) / 438

T = 2.98×10⁷ s

T = 8290 hr

T = 345 days

explanation:

earth's surface is mainly heated by the absorption of infrared radiation from the sun.

evaporation occurs because molecules in liquid water are warmed ( usually by the sun) and vibrate quicker, becoming less dense and rise.

condensation occurs because molecules in water vapor are cooled and therefore vibrate more slowly thus becoming more dense and eventually fall to earth.

lines of equal barometric pressure on a weather map are called: isobars : lines of equal temp on a weather map are called: isotherms.​