An 800-khz radio signal is detected at a point 8.5 km distant from a transmitter tower. the electric field amplitude of the signal at that point is 0.90 v/m. assume that the signal power is radiated uniformly in all directions and that radio waves incident upon the ground are completely absorbed. what is the average electromagnetic energy density at that point?

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day

search it up!

explanation:

a=d/t

a="triangle"v/t

explanation:

a = acceleration

conduct current i mean it makes sense